Answer: B 3x2 - 7x + 3 = (2x -3)2 x2 -5x + 6 =0 => x= 2 and 3 and in both cases (3x2 - 7x + 3) and (2x -3) are positive. Thus, both the value satisfy the condition. x can be 2 or 3.
Q. No. 15:
Find the value of (3log2 9/9log2 3) * (51+log52/32-log327)